聚飞光电公司简介:lim[(1-1/4)(1-1/9)...(1-1/(n+1)^2]=?

来源：百度文库编辑：高校问答时间：2024/10/04 16:11:54

lim[(1-1/4)(1-1/9)...(1-1/(n+1)^2]
=lim(1/2*3/2*2/3*4/3*3/4*5/4...*n/(n+1)*(n+2)/(n+1)
=lim(1/2*2/3*3/4*...*n/(n+1)*3/2*4/3*5/4*...(n+2)/(n+1)
=lim(1/(n+1)*(n+2)/2)
=lim(n+2)/(2*(n+1))
=1/2

lim(1/n+e^-n) lim[1-(2/t)]^3t,t趋于无穷大. lim[n(a1/n方-1)] n无限大 lim[(1-1/4)(1-1/9)...(1-1/(n+1)^2]=? 已知{an},{bn}满足lim(2an+bn)=1,lim(an-2bn)=1,求lim(anbn)的值已知{an},{bn}满足lim(2an+bn)=1,lim(an-2bn)=1,求lim(anbn)的值求一简单高数题！lim(1+1/2+1/4+1/8+~~~~+1/2n) ！1.计算lim<|x|→1>2x 1.计算lim<|x|→1>2x 求证:lim(1-1/3n)=1 (n->∞)