(4X+1)/(X-2)(X-4)=A/(X-2)+B/X-4(4X+1)/(X-2)(X-4)=(AX-4A+BX-2B)/(X-2)(X-4)(4X+1)/(X-2)(X-4)=[(A+B)X+(-4A-2B)]/(X-2)(X-4)A+B=4-4A-2B=1A=-9/2B=17/2
题目的要求呢