世界第一艾克是谁:d[(h/s)^2+1]^0.5/ds=?(h为常数)
来源:百度文库 编辑:高校问答 时间:2024/10/03 17:30:52
是不是=-s^(-2)
d[(h/s)^2+1]^0.5/ds=0.5*[(h/s)^2+1]^(-0.5)*2(h/s)*(-h/s^2)=-[(h/s)^2+1]^(-0.5)*(h^2/s^3)
d[(h/s)^2+1]^0.5/ds=0.5*[(h/s)^2+1]^(-0.5)*2(h/s)*(-h/s^2)=-[(h/s)^2+1]^(-0.5)*(h^2/s^3)