贪婪洞窟怎么玩的:一道计算题 急用
来源:百度文库 编辑:高校问答 时间:2024/08/29 02:44:50
化简或求值:(x-1)(x+1)(x^2+1)(x^4+1) (要步骤)
(x-1)(x+1)(x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
(x-1)(x+1)(x^2+1)(x^4+1)
=(x^2-1)(X^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
靠 没抄袭,这种题过程都一样
解:原式=(x^2-1(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
(不许抄袭啊!!!)
(x-1)(x+1)(x^2+1)(x^4+1)
=(x^-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
原式=(x^2-1(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1